10x^2+26x+12=6x^2

Solution for 10x^2+26x+12=6x^2 equation:

10x^2+26x+12=6x^2

We move all terms to the left:

10x^2+26x+12-(6x^2)=0

determiningTheFunctionDomain
10x^2-6x^2+26x+12=0

We add all the numbers together, and all the variables

4x^2+26x+12=0

a = 4; b = 26; c = +12;
Δ = b2-4ac
Δ = 262-4·4·12
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-22}{2*4}=\frac{-48}{8}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+22}{2*4}=\frac{-4}{8}
=-1/2
$